Y=-0.04x^2+0.32+2.5

Solution for Y=-0.04x^2+0.32+2.5 equation:

=-0.04Y^2+0.32+2.5

We move all terms to the left:

-(-0.04Y^2+0.32+2.5)=0

We get rid of parentheses

0.04Y^2-0.32-2.5=0

We add all the numbers together, and all the variables

0.04Y^2-2.82=0

a = 0.04; b = 0; c = -2.82;
Δ = b2-4ac
Δ = 02-4·0.04·(-2.82)
Δ = 0.4512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.4512}}{2*0.04}=\frac{0-\sqrt{0.4512}}{0.08}
=-\frac{\sqrt{}}{0.08}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.4512}}{2*0.04}=\frac{0+\sqrt{0.4512}}{0.08}
=\frac{\sqrt{}}{0.08}
$